Integrand size = 7, antiderivative size = 18 \[ \int (d+e x)^m \, dx=\frac {(d+e x)^{1+m}}{e (1+m)} \]
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Time = 0.00 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {32} \[ \int (d+e x)^m \, dx=\frac {(d+e x)^{m+1}}{e (m+1)} \]
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Rule 32
Rubi steps \begin{align*} \text {integral}& = \frac {(d+e x)^{1+m}}{e (1+m)} \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.00 \[ \int (d+e x)^m \, dx=\frac {(d+e x)^{1+m}}{e (1+m)} \]
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Time = 1.85 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.06
method | result | size |
gosper | \(\frac {\left (e x +d \right )^{1+m}}{e \left (1+m \right )}\) | \(19\) |
default | \(\frac {\left (e x +d \right )^{1+m}}{e \left (1+m \right )}\) | \(19\) |
risch | \(\frac {\left (e x +d \right ) \left (e x +d \right )^{m}}{e \left (1+m \right )}\) | \(22\) |
parallelrisch | \(\frac {\left (e x +d \right )^{m} d e x +\left (e x +d \right )^{m} d^{2}}{\left (1+m \right ) d e}\) | \(36\) |
norman | \(\frac {x \,{\mathrm e}^{m \ln \left (e x +d \right )}}{1+m}+\frac {d \,{\mathrm e}^{m \ln \left (e x +d \right )}}{e \left (1+m \right )}\) | \(37\) |
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none
Time = 0.28 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int (d+e x)^m \, dx=\frac {{\left (e x + d\right )} {\left (e x + d\right )}^{m}}{e m + e} \]
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Time = 0.02 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int (d+e x)^m \, dx=\frac {\begin {cases} \frac {\left (d + e x\right )^{m + 1}}{m + 1} & \text {for}\: m \neq -1 \\\log {\left (d + e x \right )} & \text {otherwise} \end {cases}}{e} \]
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none
Time = 0.21 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.00 \[ \int (d+e x)^m \, dx=\frac {{\left (e x + d\right )}^{m + 1}}{e {\left (m + 1\right )}} \]
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none
Time = 0.27 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.00 \[ \int (d+e x)^m \, dx=\frac {{\left (e x + d\right )}^{m + 1}}{e {\left (m + 1\right )}} \]
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Time = 9.62 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.00 \[ \int (d+e x)^m \, dx=\frac {{\left (d+e\,x\right )}^{m+1}}{e\,\left (m+1\right )} \]
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